`0.00050` mole of `NaHCO_(3)` is added to a large volume of a solution buffer at `pH = 8.00`. How much material will exist in each of the three forms, `H_(2)CO_(3), HCO_(3)^(-)` and `CO_(3)^(2-)` ? `K_(1)` and `K_(2)` for `H_(2)CO_(3)` are `4.5xx10^(-7)` and `4.5xx10^(-11)` respectively.

Answer

`n_(H_(2)CO_(3))= 1.069xx10^(-5), n_(HCO_(3)^(-))= 4.86xx10^(-4)`,
`n_(CO_(3)^(2-))= 2.28xx10^(-6)`;