`10mL` of `0.3M Na_(2)SO_(4)` are mixed with `20mL` solution having initially `0.1M Ca^(2+)` and `0.1M Sr^(2+)` in it. Calculate the final `[Ca^(2+)], [Sr^(2+)]` and `[SO_(4)^(2-)]` in solution? Given `K_(sp) SrSO_(4) = 7.6 xx 10^(-7)` and `K_(sp) CaSO_(4) = 2.4 xx 10^(-5)`.

Answer

`[Ca^(2+)]=3.3xx10^(-2)M, [Sr^(2+)]=1.05xx10^(-3)M`,
`[SO_(4)^(2-)]= 7.17xx10^(-4)M;`