What work is to be done on `2` mole of a perfect gas at `27^@C` if it is compressed reversibly and isothermally from a pressure of `1.01 xx 10^5 Nm^(-2)` to `5.05 xx 10^6 Nm^(-2)`? Also calculate the free energy change.

Explanation

For reversible process:
`W_(rev)=-2.303 nRT"log"_(10)(P_(1))/(P_(2))`
`=-2.303xx2xx8.314xx300 "log"_(10)(1.01xx10^(5))/(5.05xx10^(6))`
`=+1.9518xx10^(4)` joule
Since, `W_(rev)` is a measure of free energy change
`:. -DeltaG=-W_(rev)=-W_(max)`
or `DeltaG=1.9518xx10^(4)` joule