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Calculated the Gibbs energy change on di...

Calculated the Gibbs energy change on dissolving one mole of sodium chloride at `25^(@)C`.
Lattice `=+ 777.0 kJ mol^(-1)`
Hydration of `NaCI =- 774.0 kJ mol^(-1)`
`DeltaS` at `25^(@)C = 40 J K^(-1) mol^(-1)`

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`DeltaH_("dissolution")`=Lattice energy +Hydration energy
`=777.8-774.1=3.7 k J mol^(-1)`
Now, `DeltaG=DeltaH-TDeltaS`
`=3.7-298xx0.043=3.7-12.814`
`DeltaG=-9.114 k J mol^(-1)`
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