`10g` of argon gas is compressed isothermally and reversibly at a temperature of `27^(@)C` from `10L` to `5L`. Calculate `q, w, DeltaU`, and `DeltaH` for this process. `R = 2.0 cal K^(-1) "mol"^(-1), log_(10)2 = 0.30`. Atomic weight of `Ar = 40`.

Explanation

`W=-2.303 nRT"log"_(10)(V_(2))/(V_(1))`
`=-2.303xx10/40xx2xx300"log"_(10)(5)/(10)`
`W=103.635 cal`
`DeltaU=0`
`:' q= DeltaU-W`
`:. Q=-W=-103.635 cal`
Also when temperature is constant
`P_(1)V_(1)=P_(2)V_(2)` or `PV`=constant
`:. DeltaH=DeltaU+Delta(PV)=0+0=0`