In a given process on an ideal gas, `dW=0` and `dQ` is negative, then for the gas:

Options

A. The temperature will decrease
B. The volume will increase
C. The pressure will remain constant
D. The temperature will increase

Answer

A

Explanation

`q=dU+(-dW)` if `dW=0, q=-ve , dU` will be `-ve` or `T` will decrease.