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The enthalpy and entropy change for the ...

The enthalpy and entropy change for the reaction,
`Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)`
are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temperature at which the raction will be in equilibrium is:

A

`450 K`

B

`300 K`

C

`285.7 K`

D

`273 K`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaG=DeltaH-TDeltaS`
at equilibrium `DeltaG=0 :. DeltaH=TDeltaS`
or `T=(DeltaH)/(DeltaS)=(30xx10^(3))/105=285.7 K`
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