The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is:

Options

A. `DeltaG^(@)=RT ln K_(c)`
B. `-DeltaG^(@)=RT lnK_(c)`
C. `DeltaG=RT ln K_(c)`
D. `-DeltaG=RT lnK_(c)`

Answer

b

Explanation

`DeltaG=DeltaG^(@)+RTln Q`, Where `Q` is reaction quotient , At equibrium `DeltaG=0` and `Q=K_(c) :. -DeltaG^(@)=RT ln K_(c)`