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The enthalpy of vaporisation of a liquid...

The enthalpy of vaporisation of a liquid is `30 kJ mol^(-1)` and entropy of vaporisation is `75 J mol^(-1) K^(-1)`. The boiling point of the liquid at `1atm` is :

A

`250 K`

B

`400 K`

C

`450 K`

D

`600 K`

Text Solution

Verified by Experts

The correct Answer is:
b
`DeltaS=(DeltaH_(vap))/(T)`
`:. T=(DeltaT_(vap))/(DeltaS)=(30xx10^(3))/75=400 K`
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