For a particular reversible reaciton at temperature `T, DeltaH` and `DeltaS` were found to be both `+ve`. If `T_e` is the temperature at equilibrium, the reaciton would be spontaneous when :

Options

A. `T_(e)gtT`
B. `TgtT_(e)`
C. `T_(e)` is `5` times `T`
D. `T=T_(e)`

Answer

b

Explanation

`DeltaG=DeltaH-TDeltaS`
at equilibrium, `DeltaG=0` so, `TDeltaS=DeltaH`
As `DeltaH` and `DeltaS` are `+ve`, for a reaction to be spontaneous `DeltaG` should be -ve.
`TDeltaSgtDeltaH i.e,. TDeltaSgtT_(e)DeltaS`
`:. TgtT_(e)`