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The entropy change involved in the isoth...

The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of `10 dm^(3)` to a volume of `100dm^(3)` at `27^(@)C` is

A

`38.3 J mol^(-1) K^(-1)`

B

`35.8 J mol^(-1) K^(-1)`

C

`32.3 J mol^(-1) K^(-1)`

D

`42.3 J mol^(-1) K^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
a

Entropy change for an isothermal process is
`DeltaS=2.303R log((V_(2))/(V_(1)))`
`DeltaS=2.303xx2xx8.314xxlog(100/10)`
`=38.294 J mol^(-1) K^(-1)`
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