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Calculate the work done by the system, w...

Calculate the work done by the system, when `40J` heat is supplied to it, the internal energy of system increase `32J`.

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The correct Answer is:
8
`DeltaU=q+W`
`q=40 J, DeltaU=32J,W=?`
`W=32-40=-8 J`
`-ve` sign for the work done by the system
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