The elecron affinity of chlorine is `3. 7 eV`. How much energy in kcal is released when `2g` chlorine is completely converted to `cl^-` ion in a gaseous state ?
`(1 eV = 23. 06 kcal "mol"^(-10))`.

Explanation

To solve the problem, we need to calculate the energy released when 2 grams of chlorine gas (Cl₂) is completely converted to Cl⁻ ions in the gaseous state. We will follow these steps:

### Step 1: Determine the molecular weight of chlorine
Chlorine (Cl) has a molecular weight of approximately 35.5 g/mol. Since chlorine gas (Cl₂) consists of two chlorine atoms, the molecular weight of Cl₂ is:
\[ \text{Molecular weight of Cl}_2 = 2 \times 35.5 \, \text{g/mol} = 71 \, \text{g/mol} \]

### Step 2: Calculate the number of moles of Cl₂ in 2 grams
To find the number of moles of Cl₂ in 2 grams, we use the formula:
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