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Calculate the electronegativity of fluo...

Calculate the electronegativity of fluorine form the following data :
`E_(H-H) = 104.2` kcal `"mol"^(-1), E_(C-C) =83.1` kcal `"mol"^(-1)` .
`E_(C-H) =9.8.s` kcal `"mo"l^(-1)`
Electronegativity of `H=2.1`.

Text Solution

Verified by Experts

Let the electrongatibiry of fluorine be ` X_F` . Applying Pauling's eqation ,
` x_F -x-H =0.02908 [-(H-F) - (F_(F-F)xxE_(H-H))^(1//1)]^(1//2)`
` X-F=3.87`.
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