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X(Be) and S(Cl) are 1.6 and 3.2 respec...

`X_(Be)` and `S_(Cl)` are `1.6 ` and ` 3.2` respectively. Calculate Delta `H_f` for `BeCl_2` molecule .

Text Solution

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For` BeCl_2` :
`sum = 2: (X_A-X_B) =3.2-1.6 =1.6, n_N `and ` n_O =0`
`Delta H_f = 23sum (X_A -X_B)^2 -55. 4n_N -26.0n_O`
`DeltaH_f =23 xx 2 ( 1.6)^2 -55.4 xx 0- 26.0 xx0`
` =117.75` kcal "mol"^(-1)`.
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