Home
Class 11
CHEMISTRY
In the formation of N2^+ the electron is...

In the formation of `N_2^+` the electron is lost form a :

A

` sigma`-orbital

B

`pi-`orbital

C

`sigma^x` -orbital

D

`pi^x-`orbital

Text Solution

Verified by Experts

The correct Answer is:
A

M.O. configuration of `N_2` is
`sigma1s^2 , sigma^(**) 1s^2 , sigma2s^2 , sigma^(**) 2s^2 ,pi 2p_y^2 pi 2p_z^2,sigma2p_x^2`
M.O. configuration of `N_(2)^(+)` is
`sigma1s^2 , sigma^(**) 1s^2 , sigma2s^2 , sigma^(**) 2s^2 ,pi 2p_y^2 pi 2p_z^2,sigma2p_x^1` .
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING

    P BAHADUR|Exercise Exercise2B|25 Videos
  • CHEMICAL BONDING

    P BAHADUR|Exercise Exercise3|70 Videos
  • CHEMICAL BONDING

    P BAHADUR|Exercise Exercise 7|11 Videos
  • ATOMIC STRUCTURE

    P BAHADUR|Exercise Exercise 9|38 Videos
  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Exercise|134 Videos

Similar Questions

Explore conceptually related problems

In the formation of N_2^+ from N_2 , the electron is removed from

In the formation of N_(2)^(+) from N_(2) the electron is a lost from

In the formation of NO^(+) from NO, the electron is removed from

Assertion : A colloidal sol. Of Fe(OH)_(3) formed by peptisation carries positive charge. Reason : During formation of Fe(OH)_(3), the electrons are lost by the particles.

In the formation of the compound AB, atoms of A lost one electron each while stoms of B gained one electron each. What is the nature of bond in AB? Predict the two properties of AB.

If Z is atomic number of a metal, X is number of electrons lost during the formation of the metal ion from its atom, and Y is the number of electrons donated by the ligands, then effective atomic number (EAN) is

In the conversion of N_(2) into N_(2)^(+) the electron will be lost from which of the following molecular orbital ?