The hybridisation of `P` in phosphate ion `(PO_4^(2-))` is the same as in :

Options

A. ` I` in `ICl_4^-`
B. `S` in `SO_3`
C. `N` in `NO_3^-`
D. `S` in `SO_3^(2-)`

Explanation

To determine the hybridization of phosphorus (P) in the phosphate ion (PO₄²⁻) and find a compound with the same hybridization, we can follow these steps:

### Step 1: Determine the Valence Electrons of Phosphorus in PO₄²⁻
Phosphorus is in group 15 of the periodic table, so it has 5 valence electrons. The phosphate ion has a -2 charge, which means it has 2 additional electrons from the charge.

**Total valence electrons for P in PO₄²⁻:**
- Valence electrons from P: 5
- Charge contribution: +2 (due to the -2 charge on the ion)

**Total = 5 + 2 = 7 valence electrons.**

### Step 2: Draw the Lewis Structure of PO₄²⁻
To draw the Lewis structure, we need to arrange the phosphorus atom in the center with four oxygen atoms surrounding it. Each oxygen atom will form a single bond with phosphorus.

- P forms four single bonds with four O atoms.
- Each O atom has 6 valence electrons, and they will each have 2 lone pairs.

The structure can be represented as:
```
O
|
O - P - O
|
O
```

### Step 3: Determine the Hybridization of Phosphorus in PO₄²⁻
To find the hybridization, we count the number of regions of electron density around the phosphorus atom. In this case, phosphorus is bonded to four oxygen atoms, which means there are four regions of electron density.

- **Hybridization formula:**
- Count the number of bonds and lone pairs around the atom.
- 4 regions of electron density correspond to **sp³ hybridization**.

### Step 4: Compare with Other Compounds
Now we need to check the hybridization of phosphorus in the given options:

1. **ICL₄⁻**:
- Iodine has 7 valence electrons, and with 4 Cl atoms, the hybridization is sp³d² (not sp³).

2. **SO₃**:
- Sulfur has 6 valence electrons, and with 3 O atoms, the hybridization is sp² (not sp³).

3. **NO₃⁻**:
- Nitrogen has 5 valence electrons, and with 3 O atoms, the hybridization is sp² (not sp³).

4. **SO₃²⁻**:
- Sulfur has 6 valence electrons, and with 3 O atoms and 2 lone pairs, the hybridization is sp³ (this is the correct match).

### Conclusion
The hybridization of phosphorus in the phosphate ion (PO₄²⁻) is the same as in the sulfate ion (SO₃²⁻), which is **sp³** hybridized.

### Final Answer
The hybridization of `P` in phosphate ion `(PO₄^(2-))` is the same as in **SO₃²⁻**.

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