The correct order for bond angles is :

Options

A. `NO_2^+ gt NO_2gtNO_2^-`
B. `No_2^+ gt NO_2^- gtNO_2`
C. `NO_2 gtNO_2^- gtNO_2^+`
D. `NO_2^- gtNO_2 gtNO_2^+`

Answer

A

Explanation

Each has `sp^2` -hybridsation having one lone pair on ` N` in `NO_2^+`, one lone paire and one unshared pair of elctron on N in `NO_2` and tow lone pair of electrons in ` NO_2^-`. Thus bond angles are
` NO_2^+ gt NO_2 gt NO_(2)^(-) :: 180^@ gt 132^@ gt 115^@`.