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The correct order for bond angles is :...

The correct order for bond angles is :

A

`NH_4^+ gt NH_3 gt NH_2^-`

B

`NH_3 gt NH_4^+ gt NH_2^-`

C

`NH_4^+gt NH_2^-1 gt NH_3`

D

`NH_3gt NH_2^-1 gt NH_4^+`

Text Solution

Verified by Experts

The correct Answer is:
A
Each has `sp^3` -hybridisation having no lone pair in `NH_4^+`, one lone pair on `NH_3` and two lone pairs of elecron on ` NH_2^-`. Thus lone pair-lone paire repulsion is maximum in ` NH_2^-` .
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