The correct stability order for `N_2` and its given ions is :

Options

A. `N_2 gt N_2^+ gtN_2^-1 gt N_2^(2-)`
B. `N_2 lt N_2^+ ltN_2^-1 lt N_2^(2-)`
C. `N_2 gt N_2^+ ltN_2 gt N_2^(2)`
D. `N_2gt N_2^+ = N2^- gt N_2^(2-)`

Answer

A

Explanation

M.O. configuration of `N_2 : sigma 1s^2 , sigma^(**) 1s^2` .
` sigma s^2 , sigma2s^2 , [( pi 2 p_y^2) ,(pi2p_z^2)] sigma2p_x^2`
The bond order for `N_2 =3` Fro `N_2^+ = 5/2` , For
`N_2^- = 5/2` (with one moer antibonding electron than ` N_2^(+)` and 2 presoectivley . Thus Thus bond order is
`N_2 gt N_2^+ = N_2^- gt N_2^(2-)` and stability order will be
` N_2 gt gt N_2^+ gt N_2^- gt N_2^(2-)`.