`N_2` and `O_2` are converted to mono cations `N_2^+` and `O_2^+` respectively, which statement is wrong ?

Options

A. in `N_2^+` , the `N-N` bond weakens
B. In `O-2^+` , the `O-O` bond order increase
C. in `O_2^+` , the paramagnetism decrease
D. `N_2^+` become diamagnetic

Answer

D

Explanation

M.O. configuration of
` N_2 , sigma 1s^2 singa^(** )1 s^2 , sigma 2s^2 sigma^(**) 2s^2[(pi 2p_x^2) ,(pi 2p_y^2 )] sigma2 p_z^2`
` N_2^+ , 1s^2 sigma ^* 1s^2 , sigma2s^2 simga^(**) 2s^2 [ ( pi 2 p_x^2 ) ,(pi 2p_y^2)] sigma2 p_z^1`
Thus bond order for `N_2 = 1//2 [ 10-4]= 3,`
Also due to one unpaired electron `N_2^+` is paramangetic . Since bond order for `N_2^+ = 2.5` and thus `N-N` bond in `N_2^+` weakens