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2N(2)O(5) rarr 4NO(2) + O(2) If (-d[N(...

`2N_(2)O_(5) rarr 4NO_(2) + O_(2)`
If `(-d[N_(2)O_(5)])/(dt) = k_(1)[N_(2)O_(5)]`
`(d[NO_(2)])/(dt) = k_(2)[N_(2)O_(5)]`
`(d[O_(2)])/(dt) = k_(3)[N_(2)O_(5)]`
What is the relation between `k_(1), k_(2)`, and `k_(3)`?

Text Solution

Verified by Experts

For the given change
`-(d[N_(2)O_(5)])/(dt)=+1/2(d[NO_(2)])/(dt)=+2(d[O_(2)])/(dt)`
On substituting values.
`K'[N_(2)O_(5)]=1/2K''[N_(2)O_(5)]=2K'''[N_(2)O_(5)]`
or `2K'=K''=4K'''`
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