The rate of change in concentration of `C` in the reaction, `2A+Brarr 2C+3D`, was reported as `1.0` mol `litre^(-1) sec^(-1)`. Calculate the reaction rate as well as rate of change of concentration of A, B and D.

Explanation

We have, `-1/2(d[A])/(dt)=-(d[B])/(dt)=1/2(d[C])/(dt)`
`=1/3(d[D])/(dt)` = rate of reaction
`:' (d[C])/(dt)=1.0 mol litre^(-1) sec^(-1)`
`:. -(d[A])/(dt)=(d[C])/(dt)=1.0 mol litre^(-1) sec^(-1)`
`-(d[B])/(dt)=1/2(d[C])/(dt)`
`=0.5 mol litre^(-1) sec^(-1)`
`(d[D])/(dt)=3/2(d[C])/(dt)=3/2xx1`
`=1.5 mol litre^(-1) sec^(-1)`
Also, Rate=`1/2(d[C])/(dt)`
`:. Rate =1/2xx1=0.5 mol litre^(-1) sec^(-1)`