For the reaction,
`4NH_(3(g))+5O_(2(g))rarr 4NO_((g))+6H_(2)O_((g))`, the rate of reaction in terms of disappearance of `NH_(3)` is `-(d[NH_(3)])/(dt)`, then write the rate expression in terms of concentration of `O_(2), NO` and `H_(2)O`.

Explanation

To derive the rate expression for the reaction \( 4NH_3(g) + 5O_2(g) \rightarrow 4NO(g) + 6H_2O(g) \) in terms of the concentrations of \( O_2 \), \( NO \), and \( H_2O \), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Rate of Reaction**: The rate of reaction is given in terms of the disappearance of \( NH_3 \):
\[ \text{Rate} = -\frac{d[NH_3]}{dt} \]
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