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The rate of decomposition of NH(3) on pl...

The rate of decomposition of `NH_(3)` on platinum surface is zero order. What are rate of production of `N_(2)` and `H_(2)` if `k=2.5 xx 10^(-4)Ms^(-)`?

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`2NH_(3) rarr N_(2)+3H_(2)`
`-1/2(d[NH_(3)])/(dt)=(d[N_(2)])/(dt)=1/3(d[H_(2)])/(dt)`
Rate `=K [NH_(3)]^(0)`
or `(d[NH_(3)])/(dt)=2.5xx10^(-4) mol litre^(-1) s^(-1)`
`(d[N_(2)])/(dt)=1/2xx2.5xx10^(-4)`
`=1.25xx10^(-4) mol litre^(-1) s^(-1)`
`(d[H_(2)])/(dt)=3/2xx2.5xx10^(-4)`
`=3.75xx10^(-4) mol litre^(-1) s^(-1)`
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