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The rate constant for a first order reac...

The rate constant for a first order reaction is `60s^(-1)`. How much time will it take to reduce the initial concentrationof the reactant to its `1//16th` value ?

Text Solution

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`t=2.303/K loga/((a-x))`
If `a=1`, then `(a-x)=1//16`
`K=2.303/60 log 1/(1//16)=0.0462 sec^(-1)`
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