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The experiment data for the reaction 2A ...

The experiment data for the reaction `2A + B_(2) rarr 2AB` is
`|{:("Experiment",[A] M,[B_(2)] M,"Initial rate" (mol L^(-1) s^(-1)),),(I,0.50,0.5,1.6 xx 10^(-4),),(II,0.50,1.0,3.2 xx 10^(-4),),(III,1.00,1.0,3.2 xx 10^(-4),):}|`
Write the most probable rate equation for the reacting giving reason for you answer.

Text Solution

Verified by Experts

Let rate expression be: rate `=K[A]^(m)[B_(2)]^(n)`
Thus, `1.6xx10^(-4)=K(0.5)^(m)(0.5)^(n) …(i)`
`3.2xx10^(-4)=K(0.5)^(m)(1.0)^(n) …(ii)`
`3.2xx10^(-4)=K(1.0)^(m)(1.0)^(n) …(iii)`
By eqs. (i) and (ii), `n=1`
By eqs. (ii) and (iii), `m=0`
Rate`=(dx)/(dt)K[B_(2)]^(1)`
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