Home
Class 12
CHEMISTRY
Calculate the rate of reaction for the c...

Calculate the rate of reaction for the change, `2Ararr` Products, when rate constant of the reaction is `2.1xx10^(-5) time^(-1)` and `[A]_(0)=0.2M`.

Text Solution

Verified by Experts

The unit of rate constant suggest it to be first order.
Thus rate `=K[A]`
`=2.1xx10^(-5)xx0.2`
`=4.2xx10^(-6) mol litre^(-1) sec^(-1)`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 1|2 Videos
  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 3A|2 Videos
  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos

Similar Questions

Explore conceptually related problems

Select the correct option for 1st order reaction 2Ararr product having rate constant of reaction 1.386xx10^(-2) min.

The rate constant of a reaction is 2.5xx10^(-2) "minutes"^(-1) The order of the reaction is

The rate constant of a reaction is 1.2xx10^(-5)mol ^(-2)"litre"^(2) S^(-1) the order of the reaction is

The rate constant for the reaction A rarr B is 2 xx 10^(-4) mol^(-1) . The concentration of A at which rate of the reaction is (1//2) xx 10^(-5) M sec^(-1) is -

For a first order for the reaction A rarr products : the rate of reaction at [A]=0.2 M is 1.0 xx 10^(-3) mol L^(-1)s^(-1) . The reaction will occur to 75% completion in .

A to B is a first order reaction with rate 6.6 xx 10^(-5) m-s^(-1) . When [A] is 0.6 m, rate constant of the reaction is……..

For the reaction 2NOBr to 2NO_2 + Br_2, the rate law is rate = k[NOBr]^2 . If the rate of a reaction is 6.5xx10^(-6) molL^(-1)s^(-1) , when the concentration of NOBr is 2xx10^(-3) molL^(-1) .What would be the rate constant of the reaction?