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Given that the temperature coefficient f...

Given that the temperature coefficient for the saponification of ethylacetate by `NaOH` is `1.75`. Calculate the activation energy.

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Given: `K_(2)/K_(1)=1.75`
`T_(1)=25^(@)C=25+272=298 K`,
`T_(2)=35^(@)C=35+273=308K`
(Since temperature corefficient is ratio of rate constants at `35^(@)C` and `25^(@)C` respectively.)
`:' 2.303 "log" K_(2)/K_(1)=E_(a)/R[(T_(2)-T_(1))/(T_(1)T_(2))]`
`:. 2.303 log 1.75=E_(a)/1.987[(308-298)/(308xx298)]`
`:. E_(a)=10.207 kcal mol^(-1)`
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