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The specific rate constant for the decom...

The specific rate constant for the decomposition of formic acid is `5.5xx10^(-4) sec^(-1)` at `413 K`. Calculate the specific rate constant at `458K` if the energy of activation is `2.37xx10^(4)` cal `"mol"^(-1)`

Text Solution

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Given: `K_(2)=?, K_(1)=5.5xx10^(-4), R=1.987` cal,
`T_(1)=413 K, T_(2)=458 K, E_(a)=2.37xx10^(4) cal mol^(-1)`
`:' 2.303 "log" K_(2)/K_(1)=E_(a)/R([T_(2)-T_(1)])/(T_(1)T_(2))`
`2.303 "log" K_(2)/(5.5xx10^(-4))=(2.37xx10^(4))/(1.987)[(458-413)/(458xx413)]`
`K_(2)=9.38xx100^(-3) sec^(-1)`
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