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The rate constant of a certain reaction ...

The rate constant of a certain reaction is given by:
`log k= 5.4-(212)/(T)+2.17 log T`
Calculate `E_(a) at 127^(@)C`.

Text Solution

Verified by Experts

`log_(10)K=5.4-212/T+2.17 log_(10)T`
or `ln K=5.4xx2.303-(212xx2.303)/(T)+2.17 ln T`
or `d/(dt) ln K=0+(212xx2.303)/(T^(2))+2.17/T`
`d/(dt) ln K=([488.236+2.17T])/(T^(2))`
`:' d/(dt) ln K=E_(a)/(RT^(2))` (Arrhenius equation)
`:. E_(a)/R=488.236+2.17 T`
If `T=127^(@)C`
`E_(a)=2xx[488.236+2.17xx400]=2712 cal`
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