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The rate constant of a reaction is 1.5 x...

The rate constant of a reaction is `1.5 xx 10^(7)s^(-1)` at `50^(@)C` and `4.5 xx 10^(7) s^(-1)` at `100^(@)C`. Evaluate the Arrhenius parameters `A` and `E_(a)`.

Text Solution

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We know, `2.303"log"_(10) K_(2)/K_(1)=E_(a)/R[(T_(2)-T_(1))/(T_(1)T_(2))]`
`:. 2.303"log"_(10) (4.5xx10^(7))/(1.5xx10^(7))=E_(a)/8.314[(373-323)/(373xx323)]`
`:. E_(a)=2.2xx10^(4) J mol^(-1)`
Now `K=Ae^(-E_(a)//RT)`
`:. 4.5xx10^(7)=Ae^(-(2.2xx10^(4))/(8.314xx373))`
`:. A=5.42xx10^(10)`
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