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At 380^(@)C , the half-life periof for t...

At `380^(@)C` , the half-life periof for the first order decompoistion of `H_(2)O_(2)` is `360 min`. The energy of activation of the reaction is `200 kJ mol^(-1)`. Calculate the time required for `75%` decompoistion at `450^(@)C`.

Text Solution

Verified by Experts

`K_(1)=0.693//360 min^(-1)` at `653 K` and
`E_(a)=200xx10^(3) J, K_(2)=?` at `723 K, R=8.314 J`
From
`2.303 log_(10)(K_(2)//K_(1))=(E_(q)//R)[(T_(2)-T_(1))//(T_(1)T_(2))]`
`K_(2)=0.068 min^(-1)`
Now `t=2.303/0.068"log"_(10) 100/25=20.39 "minute"`
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