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What will be the initial rate of a reac...

What will be the initial rate of a reaction if its rate constant is `10^(-3) min^(-1)` and the concentration of reactant is `0.2 mol dm^(-3)` ? How much of reactant will be converted into Products in `200 min`?

Text Solution

Verified by Experts

We know,
Since `K` has unit `min^(-1)` and thus, given reaction is of `I` order.
Now, Rate `=K[ ]^(1)`
Rate `=10^(-3)xx[0.2]^(1)=2xx10^(-4) mol dm^(-3) min^(-1)`
Also `K=2.303/t"log"_(10)a/((a-x))`
`:. 10^(-3)=2.303/200"log"_(10)100/((100-x))`
`:. x=18.12%`
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