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A substance reacts according to I order ...

A substance reacts according to `I` order kinetics and rate constant for the reaction is `1 xx 10^(-2) sec^(-1)`. If its initial concentration is `1M`.
(a) What is initial rate?
(b) What is rate after `I` minute ?

Text Solution

Verified by Experts

We know,
(a) Initial rate `=K[ ]^(1)=1xx10^(-2) [1]=1xx10^(-2)`
`:. Rate =1xx10^(-2) mol litre^(-1) sec^(-1)`
(b) Now `K=2.303/t"log"_(10) a/((a-x))`
`10^(-2)=2.303/(1xx60)"log"_(10)(1)/(1-x), ( :' t= 1 "minute" =60 sec)`
`:. (1-x)=0.549`
`:.` Rate after `1` minute `=K [ ]` after `1` minute
`K=[0.549]=10^(-2) [0.549]`
Rate after `1` minute `=5.49xx10^(-3) mol litre^(-1) sec^(-1)`
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