Home
Class 12
CHEMISTRY
The rate constant of a second order reac...

The rate constant of a second order reaction is `10^(-2) "mol"^(-1) litre sec^(-1)`. The rate constant when expressed in `cm^(3) "molecule"^(-1) min^(-1)` is:

A

`9.96xx10^(-22)`

B

`9.96xx10^(-23)`

C

`9.96xx10^(21)`

D

`1.004xx10^(-24)`

Text Solution

Verified by Experts

The correct Answer is:
a
`K=10^(-2) mol^(-1) litre sec^(-1)`
`=(10^(-2)xx1000xx60)/(6.02xx10^(23)) c c "molecule"^(-1) min^(-1)`
`=9.9618xx10^(-22) c c "molecule"^(-1) min^(-1)`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 1|2 Videos

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 3A|2 Videos

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos

Similar Questions

Explore conceptually related problems

The rate constatnt of a second order reaction is 10^(-2) "mol"^(-1) litre sec^(-1) . The rate constant when expressedd in cm^(3)" molecule"^(-1) "min"^(-1) is :

The rate constant of a reaction is 3.25xx10^(-3) "mol"^(-2) "litre"^(2) "min"^(-1) The order of reaction is

The rate constant of first order reaction is 10^(-2)"min"^(-1) . The half-life period of reaction is

The rate constant of a reaction is 1.2xx10^(-5)mol ^(-2)"litre"^(2) S^(-1) the order of the reaction is

The rate constant of a reaction is found to be 3 xx 10^(-3) "mol" L^(-1) "min"^(-1) . The order of the reaction is

The rate constant of a reaction is 3.25 xx 10^(-3) " mol"^(-2) L^(2) " min"^(-1) . The order of raction is