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Consider the reaction: N(2(g))+3H(2(g)...

Consider the reaction:
`N_(2(g))+3H_(2(g))rarr 2NH_(3(g))`.
The equally relationship between `-(d[NH_(3)])/(dt)` and `-(d[H_(2)])/(dt)` is:

A

`(d[NH_(3)])/(dt)=-3/2(d[H_(2)])/(dt)`

B

`(d[NH_(3)])/(dt)=-(d[H_(2)])/(dt)`

C

`(d[NH_(3)])/(dt)=-1/3(d[H_(2)])/(dt)`

D

`(d[NH_(3)])/(dt)=-2/3(d[H_(2)])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
d
Rate of reaction
`=-(d[N_(2)])/(dt)=-1/3(d[H_(2)])/(dt)=1/2 (d[NH_(3)])/(dt)`
`:. (d[NH_(3)])/(dt)=-2/3(d[H_(2)])/(dt)`
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