The rate constant `K_(1)` of a reaction is found to be double that of rate constant `K_(2)` of another reaction. The relationship between corresponding activation energies of the two reaction at same temperature `(E_(1) "and" E_(2))` can be represented as:

Options

A. `E_(1) gt E_(2)`
B. `E_(1) lt E_(2)`
C. `E_(1)=E_(2)`
D. None of these

Answer

d

Explanation

`K_(1)=A_(1)e^(-E_(1)//RT)` and `K_(2)=A_(2)e^(-E_(2)//RT)`
`K_(1)/K_(2)=A_(1)/A_(2)xxe^((E_(2)-E_(1))RT), A_(1)` and `A_(2)` are not given.