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A substance undergoes first order decomp...

A substance undergoes first order decomposition. The decomposition follows two parallel first order reaction as:
and `KP_(1)=1.26xx10^(-4)sec^(-1)`
`K_(2)=3.80xx10^(-5)sec^(-1)`
The percentage distribution of B and C are:

A

`80%B and 20%C`

B

`76.83% B and 231.7%C`

C

`90%B and 10%C`

D

`60%B and 40%C`

Text Solution

Verified by Experts

The correct Answer is:
b
For parallel path reaction,
`K_("average")=K_(1)+K_(2)`
`=1.26xx10^(-4)+3.8xx10^(-5)`
`1.64xx10^(-4) sec^(-1)`
Also fractional yield of `B=K_(B)/K_(av)`
`=(1.26xx10^(-4))/(1.64xx10^(-4))=0.7683`
Fraction yield of `A=K_(A)/K_(av)`
`=(3.8xx10^(-5))/(1.64xx10^(-4))=0.2317`
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