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For the reaction, 2NO(g) + 2H(2)(g) r...

For the reaction,
`2NO(g) + 2H_(2)(g) rarr N_(2)(g) + 2H_(2)O(g)`
The rate expression can be written in the following ways:
`(d[N_(2)])/(d t) = k_(1)[NO][H_(2)], (d[H_(2)O])/(d t) = k_(2)[NO][H_(2)]`
`- (d[NO])/(d t) = k_(3)[NO][H_(2)], -(d[H_(2)])/(d t) = k_(4)[NO] [H_(2)]`
The relationship between `k_(1), k_(2), k_(3), k_(4)` is

A

`k = k_(1) = k'_(1) = k"_(1)`

B

`k = 2k_(1) = k'_(1) = k"_(1)`

C

`k = 2k'_(1) = k_(1) = k"_(1)`

D

`k = k_(1) k'_(1) = 2k"_(1)`

Text Solution

Verified by Experts

The correct Answer is:
b
`:' -1/2(d[NO])/(dt)=-1/2(d[H_(2)])/(dt)=(d[N_(2)])/(dt)`
`=1/2(d[H_(2)O])/(dt)`
`1/2k_(1)^(1)[NO][H_(2)]=1/2k_(I)^(II)[NO][H_(2)]`
`=k_(1)[NO][H_(2)]=1/2k[NO][H_(2)]`
`:. K_(1)^(1)=k_(1)^(II)=2k_(1)=k`
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