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The activation energies of two reactions...

The activation energies of two reactions are `E_(a1)` and `E_(a2)` with `E_(a1) gt E_(a2)`. If the temperature of the reacting systems is increased from `T` to `T'`, which of the following is correct?

A

`(K'_(1))/K_(1)=(K'_(2))/K_(2)`

B

`(K'_(1))/K_(1) gt (K'_(2))/K_(2)`

C

`(K'_(1))/K_(1) lt (K'_(2))/K_(2)`

D

`(K'_(1))/K_(1) gt 2(K'_(2))/K_(2)`

Text Solution

Verified by Experts

The correct Answer is:
b
More is energy of activation, lesser is rate constant `(K=Ae^(-E_(a)//RT))`.
Since `E_(a) gt E'_(a)`
`:. K_(1) lt K_(2)` and `K_(1) lt K'_(2)`
`:. (K'_(1))/K_(1) gt K'_(2)/K_(2)`
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