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A drop of solution (volume 0.05 mL) cont...

A drop of solution (volume `0.05 mL`) contains `3 xx 10^(-6) "mole" H^(o+)` ions. If the rate constant of disappearance of `H^(o+)` ions is `1 xx 10^(7) mol L^(-1) s^(-1)`, how long would it take for `H^(o+)` ions in the drop of disappear?

A

`6xx10^(-8) sec`

B

`6xx10^(-7) sec`

C

`6xx10^(-9) sec`

D

`6xx10^(-10) sec`

Text Solution

Verified by Experts

The correct Answer is:
c
Since rate constant `=1.0xx10^(7) mol litre^(-1) sec^(-1)`
`:.` Zero order reaction, For zero order
`t=x/K=("concentration used")/("rate constant")`
`:' 0.05 mL` has `3xx10^(-6)` moles of `H^(+)`
`:. 1000 mL has=(3xx10^(-6)xx10^(3))/(0.05)`
`=0.06 mol//litre of H^(+)`
`:. By eq. (1), t=0.06/(1xx10^(7))=6xx10^(-9) second`
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