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For a reation: A rarr Product, rate la...

For a reation: `A rarr` Product,
rate law is `-(d[A])/(dt)=K[A]_(0)`.
The concentration of `A` left after time `t` when `t=1/K` is:

A

`([A]_(0))/(e)`

B

`[A]_(0).e`

C

`([A]_(0))/e^(2)`

D

`1/([A]_(0))`

Text Solution

Verified by Experts

The correct Answer is:
a
`N/N_(0)=e^(-lambdat)=e^(-lambda(1//lambda))=e^(-1)`
`:. N=N_(0)/e`
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