Home
Class 12
CHEMISTRY
For a given reaction, presence of cataly...

For a given reaction, presence of catalyst reduces the energy of activation by `2` kcal at 27^(@)C`. Thus rate of reaction will be increased by:

A

`20` times

B

`14` times

C

`28` times

D

`2` times

Text Solution

Verified by Experts

The correct Answer is:
c
`K_(1)/K_(2)=e^(-[E_(a1)-E_(a2)]//RT)=e^(-[(2xx10^(3))//(2xx300)])`
`"log"_(e) K_(2)/K_(1)=(2xx10^(3))/(600)`
`K_(2)/K_(1)=28=r_(2)/r_(1)`
`:. R_(2)=28r_(1)`
`=28`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 1|2 Videos

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 3A|2 Videos

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos

Similar Questions

Explore conceptually related problems

In the presence of catalyst, the activation energy of the reaction is lowered by 2 kcal at 27^(@)C . The rate of reaction will increased by

A catalyst increases the rate of reaction by :

In the presence of a catalyst, the activation energy is lowered by 3 Kcal at 27^(@) c .Hence the rate of reaction will increase by :

A catalyst increases the rate of a reaction by:

At 227^(@)C , the presence of catalyst causes the activation energy of a reaction to decrease by 4.606 K cal. The rate of the reaction will be increased by : -