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For an elementry reaction aArarr product...

For an elementry reaction `aArarr` product, the graph plotted between reaction `log[(-d[A])/(dt)]` vs. time gives a straight line with intercept equal to `0.6` and showing an angle of `45^(@)` with origin, then:

A

`"rate constant"=3.98 "mol litre"^(-1) t^(-1) and a=1`

B

`"rate constant" =3.98 "time"^(-1) and a=1`

C

`"rate constant" =1.99 "mol litre"^(-1) t^(-1) and a=2`

D

`"rate constant"=1.99 "time"^(-1) and a=1`

Text Solution

Verified by Experts

The correct Answer is:
b

Rate `=-(dC_(A))/(dt)=KC_(A)^(a)`
`:. Log[-(dC_(A))/(dt)]=log K+a log C_(A)`
`:. log K=0.6`
`K=3.98 time` and `a=1=tan 45^(@)`
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