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For the reaction H(2)(g)+I(2)(g) hArr 2H...

For the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the rate of reaction is expressed as

A

(a) `(-d[H_(2)])/(dt)=(-d[I_(2)])/(dt)=(-d[HI])/(dt)`

B

(b) `(d[H_(2)])/(dt)=(d[I_(2)])/(dt)=(d[HI])/(dt)`

C

(c ) `1/2 (d[H_(2)])/(dt)=1/2(d[I_(2)])/(dt)=(-d[HI])/(dt)`

D

(d) `-2(d[H_(2)])/(dt)=-2(d[I_(2)])/(dt)=(d[HI])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
d
`(d[H_(2)])/(dt)=(-d[I_(2)])/(dt)=1/2(d[HI])/(dt)`
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