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t(1//4) can be taken as the time taken f...

`t_(1//4)` can be taken as the time taken for concentration of reactant to drop to `.^(3)//_(4)` of its initial value. If the rate constant for a first order reaction is `K`, then `t_(1//4)` can be written as:

A

(a) `0.10//K`

B

(b) `0.29//K`

C

(c ) `0.69//K`

D

(d) `0.75//K`

Text Solution

Verified by Experts

The correct Answer is:
b
`K=2.303/t"log"(a)/(a-x)`
`=2.303/t_(1//2)"log"(a)/((3a)/(4))=2.303/t_(1//4)"log"4/3`
`K=(2.303xx0.125)/(t_(1//4))=0.29/t_(1//4)`
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