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For a reaction (1)/(2)A rarr 2B, rate of...

For a reaction `(1)/(2)A rarr 2B`, rate of disappearance of `'A'` is related to the rate of apperance of `'B'` by the expression:

A

(a) `-(d[A])/(dt)=1/2(d[B])/(dt)`

B

(b) `-(d[A])/(dt)=1/4(d[B])/(dt)`

C

(c ) `-(d[A])/(dt)=(d[B])/(dt)`

D

(d) `-(d[A])/(dt)=4(d[B])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
b
`1/2Ararr 2B`
Rate`=(-2d[A])/(dt)=+(d[B])/(2dt)`
`(-d[A])/(dt)=1/4(d[B])/(dt)`
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