The half-life period of a first-order chemical reaction is `6.93 min`. The time required for the completion of `99%` of the chemical reaction will be `(log 2 = 0.301)`

Options

A. (a) `230.3 minutes`
B. (b) `23.03 minutes`
C. (c ) `46.06 minutes`
D. (d) `460.6 minutes`

Answer

c

Explanation

`K=0.693/t_(1//2)=0.693/6.93 minute^(-1)`
`K=2.303/t"log" 100/(100-99)`
`[if a=100, x=99 and a-x=1]`
`:. 0.693/6.92=2.303/t"log"100/1`
`:. t=46.06 minute`