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A reaction is first order in A and secon...

A reaction is first order in `A` and second order in `B`. How is rate affected when concentration of `B` is tripled?

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Verified by Experts

The correct Answer is:
9
Rate `r_(1)=K[A]^(1)[B]^(2) …(1)`
Now if concentration of `B` is triple
So, `r_(2)=K[A]^(1)[3B]^(2) …(2)`
Compare the eqs. (1) and (2),
`r_(1)/r_(2)=1/9 :. R_(2)=9 r_(1)`
`therefore` Rate becomes `9` times.
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